Methods and Control Structures HW
Team Teach Homework
Maze Solver Problem
Instructions
Your task is to write a method solveMaze(char[][] maze, int startX, int startY)
that determines whether a path exists from a starting point (startX, startY)
in a 2D maze to the exit marked as 'E'
. Use recursion to explore the maze.
Requirements
Input
-
A 2D array of characters (
char[][] maze
) representing the maze. -
An integer
startX
indicating the row index of the starting point. -
An integer
startY
indicating the column index of the starting point.
Output
-
Return
true
if there is a path from(startX, startY)
to'E'
. -
Return
false
if no such path exists.
Maze Rules
-
' '
represents an open path (you can move here). -
'#'
represents a wall (you cannot move here). -
'E'
represents the exit (this is the destination).
Movement
-
You can move up, down, left, or right to adjacent cells.
-
You cannot move diagonally or leave the bounds of the maze.
Marking Visited Cells
- To avoid revisiting the same cells, mark visited cells as
'#'
temporarily during recursion. Restore them to' '
after backtracking.
Steps to Solve
-
Check if the current position is valid:
-
Is it within the bounds of the maze?
-
Is it an open path or the exit?
-
-
Check if the current position is
'E'
. If yes, returntrue
. -
Mark the current cell as visited (change it to
'#'
). -
Recursively explore all possible directions (up, down, left, right).
-
If any direction leads to the exit, return
true
. -
Restore the cell to
' '
after exploring (backtracking). -
If no paths lead to the exit, return
false
.
Test Case 2: Starting at the Exit
char[][] maze = {
{'#', '#', '#', '#', '#'},
{'#', ' ', ' ', '#', 'E'},
{'#', ' ', '#', ' ', '#'},
{'#', ' ', ' ', ' ', '#'},
{'#', '#', '#', '#', '#'}
};
System.out.println(solveMaze(maze, 1, 4)); // Output: true
public class MazeSolver {
public static boolean solveMaze(char[][] maze, int startX, int startY) {
// Check if the starting point is valid
if (!isValid(maze, startX, startY)) {
return false;
}
// If the starting point is the exit, return true
if (maze[startX][startY] == 'E') {
return true;
}
// Mark the current cell as visited
maze[startX][startY] = '#';
// Explore all possible directions: up, down, left, right
if (solveMaze(maze, startX - 1, startY) || // Up
solveMaze(maze, startX + 1, startY) || // Down
solveMaze(maze, startX, startY - 1) || // Left
solveMaze(maze, startX, startY + 1)) { // Right
return true;
}
// Backtrack: Restore the cell to its original state
maze[startX][startY] = ' ';
return false;
}
// Helper method to check if the current position is valid
private static boolean isValid(char[][] maze, int x, int y) {
return x >= 0 && x < maze.length && // Within vertical bounds
y >= 0 && y < maze[0].length && // Within horizontal bounds
(maze[x][y] == ' ' || maze[x][y] == 'E'); // Open path or exit
}
public static void main(String[] args) {
char[][] maze = {
{'#', '#', '#', '#', '#'},
{'#', ' ', ' ', '#', 'E'},
{'#', ' ', '#', ' ', '#'},
{'#', ' ', ' ', ' ', '#'},
{'#', '#', '#', '#', '#'}
};
System.out.println(solveMaze(maze, 1, 4)); // Output: true
char[][] maze2 = {
{ '#', '#', '#', '#', '#' },
{ '#', ' ', '#', '#', 'E' },
{ '#', ' ', '#', '#', '#' },
{ '#', ' ', ' ', ' ', '#' },
{ '#', '#', '#', '#', '#' }
};
System.out.println(solveMaze(maze2, 3, 1)); // Output: false
char[][] maze3 = {
{ '#', '#', '#', '#', '#' },
{ '#', ' ', ' ', ' ', 'E' },
{ '#', ' ', '#', ' ', '#' },
{ '#', ' ', ' ', ' ', '#' },
{ '#', '#', '#', '#', '#' }
};
System.out.println(solveMaze(maze3, 1, 1)); // Output: true
}
}